Solving Engineering Problems in Dynamics By Michael B. Spektor

INTRODUCTION Purposeful control and improvement of how existing mechanical systems perform is an important real-life problem, as is the development of new systems. We can obtain solutions to these problems by investigating the working processes of machines and their units and elements. These investigations should be based on fundamentals of dynamics combined with a variety of related sciences. The working processes that characterize system performance can be described by mathematical expressions that actually represent equations of motion of these systems. Analyzing these equations of motion reveals the relationship between the…

Mathematical Formulas for Industrial and Mechanical Engineering

Description Mathematical Formulas For Industrial and Mechanical Engineering serves the needs of students and teachers as well as professional workers in engineering who use mathematics. The contents and size make it especially convenient and portable. The widespread availability and low price of scientific calculators have greatly reduced the need for many numerical tables that make most handbooks bulky. However, most calculators do not give integrals, derivatives, series and other mathematical formulas and figures that are often needed. Accordingly, this book contains that information in an easy way to access in addition…

Free Mathematics Questions and Answers

Free math answers are available on all types of math questions such as basic math, numbers, algebra, logarithm, trigonometry, and pre-calculus homework questions with step-by-step. In free math answers, these are the questions asked by the students to show it in step-by-step solution. 1. In a group of cows and chickens, the number of legs was 14 more than twice the number of heads. The number of cows was: (a) 5, (b) 7, (c) 10, (d) 12, (e) 14 Solution: Let the number of cows be x and their legs…

Here is a list of Algebraic formulas

Algebraic formulas a2 – b2 = (a – b)(a + b) (a+b)2 = a2 + 2ab + b2 a2 + b2 = (a – b)2 + 2ab (a – b)2 = a2 – 2ab + b2 (a + b + c)2 = a2 + b2 + c2 + 2ab + 2ac + 2bc (a – b – c)2 = a2 + b2 + c2 – 2ab – 2ac + 2bc (a + b)3 = a3 + 3a2b + 3ab2 + b3 ; (a + b)3 = a3 + b3 + 3ab(a + b) (a – b)3 = a3 – 3a2b + 3ab2 – b3 a3 – b3 = (a – b)(a2 + ab + b2) a3 + b3 = (a + b)(a2 –…